5x^2-27x-162=0

Solution for 5x^2-27x-162=0 equation:

5x^2-27x-162=0

a = 5; b = -27; c = -162;
Δ = b2-4ac
Δ = -272-4·5·(-162)
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3969}=63$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-63}{2*5}=\frac{-36}{10}
=-3+3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+63}{2*5}=\frac{90}{10}
=9
$